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6w^2-2w-280=0
a = 6; b = -2; c = -280;
Δ = b2-4ac
Δ = -22-4·6·(-280)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-82}{2*6}=\frac{-80}{12} =-6+2/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+82}{2*6}=\frac{84}{12} =7 $
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